The first factors vary fastest. most common when converting to factors). Wadsworth & Brooks/Cole. Usage expand.grid(..., KEEP.OUT.ATTRS = TRUE) Arguments... vectors, factors or a list containing these. Conversion to a factor is done with levels in the order Generate All Combinations of n Elements, Taken m at a Time Description. crossing () is a wrapper around expand_grid () that de-duplicates and sorts its inputs; nesting () is a helper that only finds combinations already present in the data. Usage expand.grid(..., KEEP.OUT.ATTRS = TRUE, stringsAsFactors = TRUE) Arguments... vectors, factors or a list containing these. Create a data frame from all combinations of the supplied vectors or factors. For k = 2, it's pretty easy. I've a data frame with n rows, and I want to apply a function on all possible combinations of k rows of this data frame. Actually, these two methods are slower (see below in reprex), and I won't gain anything other than learning a new alternative (which is important, I understand). How to filter for unique combination of columns from an R dataframe. expand () generates all combination of variables found in a dataset. It is paired with nesting () and crossing () helpers. expand () generates all combination of variables found in a dataset. It is not more efficient I guess but it could be easier to read and to clarify the step. Chambers, J. M. and Hastie, T. J. If x is a positive integer, returns all combinations of the elements of seq(x) taken m at a time. I tried with a dataframe of 20 rows and 7 groups, and the time difference is really significant. attribute (see below) should be computed and returned. I can find the relevant row numbers from the output of tidyr::crossing(., .) See the description of the return value for precise details of I'm not sure how it performs relative to base R, but I typically prefer the most readable and/or compact option unless I'm optimizing a bottleneck. Cheers! The row names are ‘automatic’. But I suppose there's a better way and at least for me, the pattern of the row indices is not that obvious. Create a data frame from all combinations of the supplied vectors or factors. If I can create another data frame which has \binom{n}{k} rows corresponding to the all possible row combinations,then I can simply use my function using apply on the rows. It's much faster than the previous solution by Christophe. Viewed 50k times 29. factors. Hello, I need to create a dataframe containing all possible combinations of three variables: SITE (101,102,103,104), WDAY (MON,TUE,WED,THR,FRI), and TOD (MORN, AFTN). KEEP.OUT.ATTRS: a logical indicating the "out.attrs" attribute (see below) should be computed and returned. logical specifying if character vectors are Value. Created on 2019-03-24 by the reprex package (v0.2.1). My question is how to create such a data frame. But I'm trying to learn tidyverse and hence I wonder whether there's a way to do this in tidyverse. Create a Data Frame from All Combinations of Factor Variables Description. Active 3 years, 7 months ago. The following is what my data looks like . Please use reprex::reprex_rescue() for this part. 6. Create a data frame from all combinations of the supplied vectors or factors. they occur in the character vectors (and not alphabetically, as is Attribute "out.attrs" is a list which gives the dimension and expand () is often useful in conjunction with joins: Can these two be modified to perform better? of all combinations of n elements, taken m at a time. See the description of the return value for precise details of the way this is done. If x is a positive integer, returns all combinations of the elements of seq(x) taken m at a time. You can also try this tidyverse alternative. Main task is the reshaping to meet you expected output shape. dimnames for use by predict methods. Ask Question Asked 8 years, 11 months ago. rdrr.io Find an R package R language docs Run R in your browser R Notebooks. The columns are labelled by Podcast #128: We chat with Kent C Dodds about why he loves React and discuss what life was like in the dark days before Git. Hi! Create a data frame from all combinations of the supplied vectors or factors. There is also a way with less steps but more cryptic and advanced as it uses the power of purrr::pmap(). There should be a total of 40 unique combinations in my dataframe. a logical indicating the "out.attrs" This topic was automatically closed 7 days after the last reply. converted to factors. components of a list. But if I have to use combn, then I guess I'll prefer base approach, as I understand what it's doing much better, as of now. Here is a way using tidyverse. crossing () is a wrapper around expand_grid () that de-duplicates and sorts its inputs; nesting () is a helper that only finds combinations already present in the data. To find all unique combinations of x, y and z, including those not present in the data, supply each variable as a separate argument: expand(df, x, y, z).. To find only the combinations that occur in the data, use nesting: expand(df, nesting(x, y, z)).. You can combine the two forms. Generate All Combinations of n Elements, Taken m at a Time Description. Create a data frame from all combinations of the supplied vectors or New replies are no longer allowed. Columns can be atomic vectors or lists. Statistical Models in S. Create a Data Frame from All Combinations of Factor Variables Description. See the description of the return value for precise details of the way this is done. After you created the DataFrame in R, using either of the above methods, you can then apply some statistical analysis. the way this is done.
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